3x=(7x-2)((4x+4/7x-2)^2)

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Solution for 3x=(7x-2)((4x+4/7x-2)^2) equation: 



3x=(7x-2)((4x+4/7x-2)^2)

We move all terms to the left:

3x-((7x-2)((4x+4/7x-2)^2))=0



Domain of the equation: 7x-2)^2))!=0

x∈R



We multiply all the terms by the denominator


3x*7x-2)^2))-((7x-2)((4x+4=0

Wy multiply elements

21x^2-2)^2))-((7x-2)((4x+4=0

We move all terms containing x to the left, all other terms to the right

21x^2-2)^2))-((7x-2)((4x=-4

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